Given a pattern and a string str, find if str follows the same pattern.

Examples:

1. pattern = "abba", str = "dog cat cat dog" should return true.
2. pattern = "abba", str = "dog cat cat fish" should return false.
3. pattern = "aaaa", str = "dog cat cat dog" should return false.
4. pattern = "abba", str = "dog dog dog dog" should return false.

 

Notes:

1. patterncontains only lowercase alphabetical letters, and str contains words separated by a single space. Each word in str contains only lowercase alphabetical letters.
2. Both pattern and str do not have leading or trailing spaces.
3. Each letter in pattern must map to a word with length that is at least 1.

Runtime: 0ms

 

1 class Solution { 2 public: 3     bool wordPattern(string pattern, string str) { 4         if(pattern.empty() && str.empty()) return true; 5         if(pattern.empty() || str.empty()) return false; 6          7         unordered_map
     
       p2s; 8         unordered_map
      
        s2p; 9         10         vector
       
         vec;11         int start = 0, end = 0;12         while(end < str.size()){13             while(end < str.size() && str[end] != ' ')14                 end++;15             vec.push_back(str.substr(start, end - start));16             start = end + 1;17             end = start;18         }19         20         if(pattern.length() != vec.size()) return false;21         22         for(int i = 0; i < pattern.size(); i++){23             if(p2s.find(pattern[i]) == p2s.end())24                 p2s[pattern[i]] = vec[i];25             else26                 if(p2s[pattern[i]] != vec[i]) return false;27                 28             if(s2p.find(vec[i]) == s2p.end())29                 s2p[vec[i]] = pattern[i];30             else31                 if(s2p[vec[i]] != pattern[i]) return false;32         }33         return true;34     }35 };